I have 2 tables called: sites and regions. I am performing a seach of the sites table where the postcode is like "nn" for e.g. Along with the result set from the sites table, i'm trying to display the 'town' field belonging to the regions table. Code:
How do i nest one mysql query within another (for cross referencing another table in the middle of that first query)? for example:
i am referencing a table with news posted by members and in the middle of that reference i want to reference an up to date version of their email address as listed in their profile (in case they change it after posting a news message).
I have problems with a query that involves three tables. Table contacts: contact_id, contact_name Table companies: company_id, company_name Table ref_company_contacts: ref_id, contact_id, company_id If i want to get contacts for a company the query goes like this: PHP Code:
$companyId = 3;
$sql = "SELECT contacts.* FROM contacts, companies, ref_company_contacts"; $sql.= " WHERE companies.company_id = '$companyId'"; $sql.= " AND companies.company_id = ref_company_contacts.company_id"; $sql.= " AND ref_company_contacts.contact_id = contacts.contact_id";
But what shall i do if i want to select only the contacts in table "contacts" that not have a referanse to the company in table "ref_company_contacts".
users = user data games = game data my_games = relationships user id and game id
So i need to know how I can take the data in the my games table and kind of reverse lookup the gid or uid to return the correct record. What im trying to do is on user profiles have a list of there games there playing.
Name | VARCHAR Email | VARCHAR Age | TINYINT | NULL (Default: NULL)
And I want the user to enter his or her name, email, and age - but AGE is optional.
My insert would look something like:
INSERT INTO data (Name, Email, Age) VALUES ('$name', '$email', $age)
This is all good, except if the user doesn't enter an age. Then $age is an empty variable. I thought that since the table is set up where Age can be NULL, that this should be fine. But MySQL is giving me an error. If $age is a number, it is no problem.
With this (testing) code I create a form to update prices in my database. (colums: id, omschrijving, prijs). The textboxes have the same id as the id-number in the database.
I would like to receive some help to write the update query. The query must handle all the id's, not row by row (id1 = field1, id2 =field2 etc), because the number of items is changing in the coming time. Code:
Running an EXPLAIN on some of my query tests have resulted in slow ALL joins even with indexes. How do I make a MYSQL query with the following information more efficient?
counter: id (pk), timestamp, user_id (fk) user: id (PK), username, website_id (fk) website: id (pk), sitename SELECT t2.username, t3.sitename, count(*) as views FROM counter t1 LEFT JOIN user t2 ON t2.id = t1.user_id LEFT JOIN website t3 ON t3.id = t2.website_id WHERE t1.id <> "" GROUP BY t1.id ORDER BY t1.id DESC
I am having two tables and I want to move the data from one table to another using mysql query. All the fields of first table(from which I want to move data) are in second table and two extra fields are there. I want to move the data of first table to second table when certain condition is satisfied. So, I have written query like,
insert into table2('field1','field2','field3','field4','field5') select 'field1','field2','field3' from table1 where 'field1'<1,'field4 value','field5 value';
But it gave me error when I ran it.. What exactly I want to do is to insert all the values of first table into second one and two extra fields that are present in the second table. But I am not able to insert.
im having a problem regrading a query which will update earning table with another random value from users table.when executing the query it do nothing
$update = mysql_query("UPDATE earnings SET userid = (SELECT ID FROM users WHERE installid is NULL ORDER BY rand()) WHERE userid='0'"); in the second query SELECT ID FROM users WHERE installid is NULL ORDER BY rand()
it will get me a random userid where installid null
To preface my question I am a rookie in the PHP area, so forgive my incompetence. I am performing a query on a MySQL table and displaying the fields in a HTML table supported by DataTables, and due to the number of records I have stored in my table (5000+ rows) i have a big problem with the initial load time. I am using caching methods to enhance navigation beyond the initial load, however I still need a solution for reeling in the carp. I wanted to use the js datatables plugin to allow users quick access to paginated data, but if the load time hogs their memory and delays first glance...obviously I need to go a different route.
I have just created a shopping cart and I would like to send my user the receipt of there order by email. The receipt is generated by a mysql query and is displayed within a table. I have worked out how to send a html using simple HTML code as my â€ś$messageâ€� variable: $success = mail($to, $subject, $message, $headers);
But I can not get it to send my mysql query result displayed in a table. How can i create the result of my mysql query and make it a simple variable i.e $message.
Want to list all the song for the the album and want to list all the artist for individual song.1.Song Title 1- Artist 1, Artist 2, Artist 3.note:(all this individual artist have link to there artist page)2.Song Title 2- Artist 1, Artist 2.3.Song Title 3- Artist 1, Artist 2, Artist 3.Tables are song, album, artist, song_artist.
Code:song table +----+-----------+----------+ | id | song_name | album_id | +----+-----------+----------+ | 1 | Title 1 | 2 | | 2 | Title 2 | 2 | | 3 | Title 3 | 2 | +----+-----------+----------+