Mysql UPDATE Syntax

Dec 7, 2000

what is wrong with this code? It generates no erros, but doesn't work either:

$query = "UPDATE $usertable SET dl=dl+1 WHERE id=$id";
$result = MYSQL_QUERY($query);

There is a unique id number for every row in my table. There is also a column called "dl" which holds the number of downloads certain files have gotten. I'm trying this code on my download page so that every time someone downloads a file (identified by its id number) the "dl" column for that file is incremented.

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Mysql Update/replace Syntax

Jul 17, 2005

To keep track of how many fruits my visitors buy, I use a mySQL database
(2 columns: "fruit" and "quantity")....so can we make these following
mySQL queries work somehow?

(visitor buys 5 apples):
replace into fruit_database set fruit = 'apple' , quantity = quantity +
5;

(visitor buys 7 apples):
replace into fruit_database set fruit = 'apple' , quantity = quantity +
7;

(visitor buys 1 grape):
replace into fruit_database set fruit = 'grape' , quantity = quantity +

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Php - Update Mysql Database - Syntax Error

Jun 7, 2007

When i try and update the database table i get this error.

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc='My name is ***** and I'm a 17-yr. old junior. I play electric ba' at line 1

what i am doing is having the user fill in a large text area and saving it to a database. So i think the problem could possibly be that they are using ' and " in textarea to mess it up? Code:

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Feb 27, 2006

I'm using this query for an update form: Code:

$sqlUpd = "UPDATE employee SET fname = '$fname', lname = '$lname', title = '$title', email = '$email', id = '$id', pass = '$pass', all='$all', prepare_user_quotes = '$prepare_user_quotes', manage_jobs='$manage_jobs', manage_users='$manage_users', add_employee='$add_employee', add_process='$add_process', add_news_story='$add_news_story', add_dyk_tip='$add_dyk_tip', create_mail_list='$create_mail_list' WHERE unique_id='$val'" OR die(mysql_error());

but always seem to get a syntax error. I've tried all the available methods, but still syntax error pops up. This is the error I'm getting: Code:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'all=Ƈ', prepare_user_quotes = Ƈ', manage_jobs=Ɔ', manage_users=Ɔ', add_emplo' at line 1

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Mysql Syntax Correct For Update/Insert If Exists?

Feb 10, 2011

My plan is to update/insert existing/new records into a database from an external, i have the information set to go into the database, but cannot check if it exists already.

my first attempted at doing database stuff

$link = resdb::connect();
$q = "IF ( EXISTS ( SELECT * FROM property AS this WHERE this.name = $propertyname ) )"
."begin"
// UPDATE PROPERTY IF IT EXISTS
."UPDATE property (name, propertylocation, propertyrating, propertytype)"
."SET ($propertyname, $locationid, $ratingid, $typeid)"
."WHERE name = $propertyname"
."end"
."ELSE"
."begin"
."INSERT INTO property (name, propertylocation, propertyrating, propertytype)"
."VALUES ($propertyname, $locationid, $ratingid, $typeid)"
."end";
$r = mysqli_query($link, $q);
if($r > 0){
return true;
}

A unique id is made on completion of each row.

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Feb 7, 2010

i keep getting this error no matter what format I use in updating the database.

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''inbox' SET delete = '1' WHERE mailID = '218'' at line 1

the tabels i have are

Trevors4_MTD
inbox
lastonline[code]....

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SQL Syntax Error - MySQL / Check The Manual That Corresponds To Your MySQL Server Version For The Right Syntax To Use Near 'And Role?

Nov 7, 2009

I'm not sure why this code is not working and throwing the following error:

You have an error in your SQL syntax, check the manual that corresponds to your MySQL server version for the right syntax to use near 'AND role != 7 AND role != 4' at line 3

$sql = 'SELECT * FROM tblusers
INNER JOIN permissions on tblusers.usrID = permissions.user_id
WHERE permissions.team_id='.$team_id.' AND role != 7 AND role != 4';
require("connection.php");
$result = mysql_db_query($DBname,$sql,$link) or die(mysql_error());
code....

I know that the variable $team_id is working fine, because if I "echo" it, it works fine.

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Sep 2, 2010

I keep getting this error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 2

When I use the script below. I'm finding it a bit confusing because everything about it continues to work, it's just it gives me an error. When the script runs, the outcome is
Followed by the error, which cuts the remainder of the page off. Does anybody know why it's doing this?

$dogyay = $_POST['dogid'];

$checkenergy = "SELECT energy FROM dogs WHERE id=$dogyay";  
$energylevel = mysql_query($checkenergy) or die(mysql_error());[code].....

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May 24, 2006

Have a little problem I need a second set of eyes to fix please - more I stare at it, more annoyed I become. ERROR:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 9.

SYNTAX
$query = "UPDATE user
SET
Username='$Username',
Password='$Password',
FirstName='$FirstName',
LastName='$LastName',
Email='$Email',
AccessLevel= $AccessLevel
WHERE UserID={$_GET['UserID']}";

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Apr 25, 2011

My friend has a script that updates a table called 'parent' in the database with the mobile and email address. I had a lot of issues with his scripts,. This is the script:

Code:

<?php
$parentName = $_POST ['parentName'];
$pmobile = $_POST ['pmobile'];[code]...

The issue is in the MySQL query and I get the error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(pmobile, pemail) SET pmobile = '', pemail = '' WHERE parentName = ''' at line 1

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Jan 27, 2010

the statement:

SET @v1 = 5; select @v1

the mysqli error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '; select @v1' at line 1

This runs just fine in phpmyadmin though. What's the problem with running it with mysqli ? The prepare fails.

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Jan 3, 2007

When I use my php script I get this error:

You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near &#3912;'' at line 1

The code:

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Jul 4, 2011

I need help with this code:

$mdl = Doctrine_Query::create()
->update('Model_CoachsTownsLang ctl')
->set('ctl.Coachs_Users_id', '1')[code]....

ZFDebug output error: Doctrine_Connection_Mysql_Exception: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'sdfg sdfg , active = 1, description =...

But I look at this code and I see no errors in syntax.Tabla adds structure to the database:

CREATE TABLE IF NOT EXISTS `intelektualnie`.`CoachsTownsLangs` (
`id` INT NOT NULL AUTO_INCREMENT ,
`Coachs_Users_id` INT NULL [code]....

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You Have An Error In Your SQL Syntax; Check The Manual That Corresponds To Your MySQL Server Version For The Right Syntax To Use Near '' At Line 1

Jun 28, 2007

I can't figure out whats wrong witht his query.

Quotemysql_query("INSERT INTO `serverInfo` ( `id` , `serverid` , `size` , `filename` , `timestamp` ) VALUES('null', '1', '".$size."', '".$dir."', '".$date."'") or die(mysql_error());

Anything stupidly wrong here? the id,serverid, size, filename,timestamp thsoe are all right.

Error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

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Oct 9, 2006

mysql_query("UPDATE scfmforening SET scfmpad=$scfmpad, scfmpnm=$scfmpnm,
scfmort=$scfmort, scfmwww=$scfmwww, scfmwww=$scfmwww, scfmept=$scfmept,
scfmkom=$scfmkom WHERE scfmnum=$scfchknum ");

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Apr 19, 2006

How do I run an update query based on the submission of a form which edits a current record? Code:

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Sep 7, 2005

how can i get all this in one query?

$query2 = "update Reviews set Title='$Title' where ID='$ID'";
$result2 = mysql_query($query2);
$query3 = "update Reviews set Description='$Description' where ID='$ID'";
$result3 = mysql_query($query3);
query4 = "update Reviews set name='$name' where ID='$ID'";
$result4 = mysql_query($query4);...........

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Oct 5, 2003

I'm having some trouble getting my database to update. This is my first attempt at PHP and MySQL and so far I'm doing well. I just used some of the code from the tutorials on this site and changed them to suit my needs. Everything works except updating the database. Clicking edit swaps a row in a table with a form that should allow me to update the entry. Here is the error it throws.

You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3
I have followed the correct syntax as far as I can tell, but like I said, this is my first time with PHP and MySQL. Following is all my code (minus CSS which has nothing in it really) with the appropriate sections highlighted.

Code:

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May 8, 2010

[URL].........I was not able to understand this part of the code written by the uthor.list($sets,$cols,$values)=escape_arr($sets);

[code]............

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Apr 15, 2006

This is a code from A-Mod, but doesn't see like no one really cares..so thought I'll post it here and maybe I'll get some help. When I'm on activity.php and click next page I get the following error: Couldn't obtain game data DEBUG MODE

SQL Error : 1064 You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5 Code:

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Mar 11, 2006

I'm trying to update multiple columns at once in my database. The updated information is coming from another form page. This is my code and below it is the error. I have also tried this with single quotes and no brackets and I receive the same error message without the brackets with quotes. Code:

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May 7, 2010

im putting the following code into a mysql database

$killersmessage = "You have collected a bounty of $" . "$english" . "for killing <a href='viewuser.php?u=" . "$victim" . "'>" . "$victimname" . "</a>";

but i get the error

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'viewuser.php?u=2'>shadow72')' at line 2

anyone got how i can get it to work?

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Apr 3, 2010

I have written a very simple function:

function editCategory() {
$ID = urlencode($_GET['id']);
$cname = mysql_fix_string($_POST['cname']);

[code]...

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1.

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May 17, 2007

Not sure how the syntax is supposed to work for Update Queries with POST data. 

$q = "UPDATE articles SET sub=$_POST['c'],
title=$_POST['t'],
name=$_POST['n'],
email=$_POST['e'],
date=$_POST['d'],
description=$_POST['d'] WHERE id=$_POST['articleid'] LIMIT 1";

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Jul 1, 2010

Well after scratching my head for too long, I give in, I've got to ask or I'll go crazy! I've been fiddling with PHP/MySQL again recently and although I successfully get a search of the db via a form field and have found a way* of adding a checkbox and update multiple records (a popular request I think!), my next hurdle is combining them.

I was hoping I could mash the script together (logically with my limited knowledge) to produce a 3 stage script. Page1 would send Page2 the search term (works so far) and then Page2 would send itself(and the db) those recorded selected for updating.

So far, when I try to I'm getting many errors, and I believe they occur because the script is trying to get information that's not there (from the search). Also it's because I've tried to modify existing code and I'm really guessing now :-(

Here's the code on the second page, the first page simply has a $_POST in it and then the second page collects that info:

[Code]...

It might be worth knowing that security isn't an issue as this script is run offline via WAMPServer (a brilliant freebee for testing!). Well, I really look forward to any comments,

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May 3, 2011

how yo use hyperlink update to update values inside Mysql database via textboxes .

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Nov 12, 2008

well i have this messages table with sample values like these:

msg_id recipient_id read locked new
0 1 N Y Y
2 1 Y N N

ok, so lets just say this is a messaging table, and i want to reset all messages addressed to recipient with id=1 i was wondering why UPDATE `messages` SET `new`='Y',`read`='N',`locked`='N' where `recipient_id`=1;

doesn't work, MYSQL always returns 0 affected rows.. to robert gamble: yes, im sure the values were changed, since my purpose for this update query is to reset the data i was using for the testing phases :D

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Jul 17, 2005

I use a function, myrandomPIN (), to generate random PIN numbers.

The following sql query updates records with the SAME PIN number but.
I want to generate DIFFERENT pin numbers for every record. The
function is ok but I can't figure out how to run it individually for
each record. In other words I do not know the correct syntax to use
UPDATE in a loop (if necessary) so that a different call to the
function is done every time or ecah record ends up with a different
PIN.

Or may be this can be done with a single mysql_query($sql2)?

--------------------------------------------------------------------------
$qr = @mysql_query($sqlb1) or die("ERROR");
$rs1 = mysql_fetch_array($qr);
$thepin=myrandomPIN();
$sql2="UPDATE clients SET pin='$thepin' WHERE code='".$thecode."'";
$qr = @mysql_query($sql2) or die("ERROR"");
--------------------------------------------------------------------------

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Mar 14, 2011

Whenever I try to update any piece of PHP code to update a MySQL database, nothing happens. I have tried copying in some of the working codes of a website and tried the same, but no success. I recently installed XAMPP. I am connecting using the correct user id and pass to the database. The scripts are not giving me any error, but just not connecting, that's all.

While making such a usage as noted below <FORM name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" >

I get the following error Firefox can't find the file at /C:/xampp/htdocs/="<?php..  so on

Why does this happen?

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Jun 2, 2011

an update was successful when data sent to update was the same as that already in DB?Can it be done without selecting it before/after?

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Mar 21, 2007

I have a basic db that I access with MySQL query browser. Everything
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Notice: Query failed: You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near '>function.extract]: First argument should be an
array in functions.inc.php on line 31
Notice: Undefined variable: price in functions.inc.php on line 36
Notice: Undefined variable: price in functions.inc.php on line 39
Notice: Undefined variable: total in unctions.inc.php on line 39

I'm assuming the last three are caused by this problem as price should
be passed to the cart, and total is worked out using it. However
although I know mySQL code it was the MySQL query browser that
actually generated the code and I cannot see a way to view or debug
the code.

The db has one table in it which is made up of id, name, subname,
desc, and price.

The code in the php file that is being referred to is:

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Sep 1, 2010

First up, apologies for the awful title I couldn't think of a better way to articulate my issue. (Feel free to suggest better altnernatives)Basically I have a table with a "count" column.I want to reset all counts to zero except for the 10 rows with the top values. I want them to be reset to 0.How do I achieve this without writing multiple queries?

Update ,I have my query as the following now

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Feb 4, 2011

I'm assuming that it has something to do with whats inside one of the variables i'm trying to insert into the database. But after looking at them (print_r($var);), they seem fine. I don't know why I'm getting this vague as hell error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5 Here's code from line 0 through to where there's no more php/mysql stuff:

[code]...

Syntax looks normal to me, and I've checked the values of all the variables that are being inserted into the db, and they're fine.

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Oct 5, 2010

What is wrong with the "update" row .... it is showing some syntax error

$sql="SELECT * FROM contact";
$result=mysql_query($sql);?>
<table align="center" width="700" border="0"><tr><td><?php[code]....

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Oct 14, 2001

sorry to cross post this, but i know most of you at least dabble with mysql, and this forum seems a bit more active than the mysql one so here goes...

This is what i'm trying to do.....
IF EXISTS (tablename)
#update some fields
ELSE
CREATE TABLE tablename(
#fields
);
INSERT INTO tablename all the values i need.

Seems straight forward, but can't figure it out

Tried every permutation of IF TABLE EXISTS and also tried
IF EXISTS (SELECT * FROM tablename)
but they both give errors.

Thanx for any help with this one, it's driving me nuts.

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May 14, 2007

I have this right now:
SELECT title, COUNT(*) as numissues FROM comics WHERE type ='Comic Book' GROUP BY title"

But I need something like:
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The second line doesn't work. How would I get it to select where IS NULL and also Comic Book?

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Jul 11, 2007

What would be the syntax of a mysql query when I want to pull the id and another specific column in a row. example:

$sql = 'SELECT * FROM products WHERE id = '.$id.', boy = '.$_POST["boyGirl"];

right now I get this error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' boy =' at line 1 SQL: SELECT * FROM products WHERE id = 5, boy = in /home/realfina/public_html/thediaperbakery/inc/mysql.class.php on line 107

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Jul 17, 2005

for php syntax when i call Mysql database

I have wrote that and my sql connection is working

I just have a problem with this command line :

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Jul 26, 2005

i started writing a litte cli script that should simply perform one "insert" command. but everytime i execute this litte script i get a sql syntax error. when i execute my query via phpmyadmin i get no errors and everything is ok. Code:

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Dec 19, 2005

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DROP DATABASE /*! IF EXISTS */ students' at line 1

Could someone simply tell me why in the world this would produce a syntax error? I have permissions to CREATE and DROP DATABASE; in fact, the database is always successfully created and/or dropped, nonetheless, I always get errors (and 1 warning).

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Feb 12, 2007

I am trying to revoke a user i made to the database "mysql". I typed this command and it doesnt seem to work:

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Grants for pat@localhost
GRANT USAGE ON *.* TO 'pat'@'localhost' IDENTIFIED BY PASSWORD
GRANT ALL PRIVILEGES ON `vbox_vbox`.* TO 'pat'@'localhost'
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Nov 4, 2006

im trying to do a basic search query but i cant quite get the syntax down for what I want to do. I have something like this, im not quite sure what im missing. PHP Code:

$search =$_POST['txtSearch'];
echo "This is the search query: ". $search;

$sql = "SELECT * FROM articles WHERE message LIKE '%search%' ORDER BY id DESC LIMIT $from, $max_results";

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Feb 22, 2006

This is what i'm trying. And you can guess what i'm trying to do. Is this the correct way of doing it or can it not be done.

$pm_query = mysql_query("SELECT * FROM messages WHERE username = '$username' AND status = 'read' or 'unread'")

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Oct 5, 2005

$select = "SELECT DISTINCT firstname, lastname, street1, street2, city, state, zipcode, zip4, country, countrycode, MAX(quantity) FROM moms_customer, moms_lists WHERE moms_customer.custnumber = moms_lists.custnumber AND pubid IN($display) GROUP BY lastname";

When i run it on a server with mysql version 4.0.25 it runs fine. When I run it on a server with mysql version 4.1.8 I get the following error. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') GROUP BY lastname' at line 1

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Nov 24, 2010

Is there something wrong with the syntax on this MySQL query?

$ttquery = sprintf("Update login SET ".$row['ttemail']." = '1' WHERE username = ".$row['username']."");

EDIT: Okay, per Pekka's request, I echoed out the actual query value, and that gave me some ideas. Now I'm using this:

$ttquery = "Update login SET ttemail = 1 WHERE username = ".$row['username']."";

and I get this error: Unknown column 'admin' in 'where clause'. "admin" is the first username that meets the condition I want to run this query for... it's not the name of a field. Any ideas on why I'm getting the error

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