Sep 12, 2007

is there a possibillity to check how the user-file field is set ?

I tried :


print"<form method=POST action=$_SERVER[PHP_SELF] enctype=multipart/form-data>";


$im_set = "SET";
echo $im_set;
$Im_notSet = "NOT SET";
echo $Im_notSet;

<input name="userfile" type="file" class="forms" size="30">

...but it doesn't work it always returns that it is set.

View 3 Replies


Passing $_FILES['userfile'] Into Function Does Not Work?

Code is worth a millions words so, here is what I am trying to do:

<form enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="10000000" />
<input name="userfile[]" type="file" />
<input type="submit" value="Submit" />


Warning: file_get_contents() expects parameter 1 to be string, array given in /path/Pimage.php on line 47

Warning: getimagesize(Array) [function.getimagesize]: failed to open stream: No such file or directory in /path/Pimage.class.php on line 48

Anyone have any clues as to why the ECHO's are not working? Why does $image[name] not echo out the name?

View 1 Replies

Any Reason Why $_FILES['userfile']['error'] Wouldn't Be Populated?

I am in the middle of writing an image upload script and am limiting
the size of uploads via upload_max_filesize. This all seems to be
working well, and if I try and upload a bigger file then I get an
UPLOAD_ERR_INI_SIZE sat in $_FILES['userfile']['error']. All hunkey

However, in my testing there are one or two large files that cause
problems. PHP appears to abort the upload early as it should, but when
my script runs, $_FILES isn't populated at all?!

I have tried to narrow down the difference in these file but I can't
seem to find anything definate. All the ones that fail are AVI or WMV
files if that gives any clue, but even if I rename them to MPG (others
of which work ok), and check the MIME type being sent up has also
changed to mpg, then they still fail as before. I have sent bigger and
smaller files all ok, so it's not size. I can't see anything in the
filename itself that would cause problems.

View 3 Replies

File Upload - The $_FILES['userfile'] Doesn't Actually Get The Data And Store It

the $_FILES['userfile'] doesnt actually get the data and store it. I thought maybe its because of the $_GET method which it still maybe but I worked on this for ver long. I tried echo'ing the data in the $fileType, $fileSize, etc and its empty so theres a problem with the data being parsed. below is the code

$fileName = $_FILES['userfile']['name'];
$tmpName = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];
$filePath = $uploadDir . $fileName;
<input name="userfile" type="file" id="userfile">

View 4 Replies

Control The Size Of Uploads Using $_FILES['userfile']['size'] > Xxx?

I know you can control the size of uploads in PHP using $_FILES['userfile']['size'] > XXXMy question I suppose is performance related.When you upload a file, my understanding is the whole file gets uploaded to a temporary location, and then you have access to $_FILES What happens if a user attempts to upload a 10gb file? (as an example of a very large file)If a large file is attempted to be uploaded, does this waste server bandwidth as the file needs to be uploaded before it can be processed/validated.I know PHP has like timeouts etc but I'm curious if there is a performance impact from users attempting to upload very large files, even if (for example) the max file size is 2mb.Is this a concern or something unavoidable and just to not worry.

View 2 Replies

How Do I Check If The $_FILES Isset?

I have a form that allows five photo uploads at once. The thing is when the user uploads only one photo that should be it... but it still tries to upload and move the other, non existent photos. I have an if statement that does not seem to be working....

here it is:

View 2 Replies

Userfile Size?

I know there is a userfile_size for when you upload a file. But is there any way to actually figure out that dimensions of the image. Say to limit the image to only being 85 by 110. Also is there anyway to store the value of image dimensions in a database?

View 1 Replies

Userfile Exists

I have a script working for uploading a photo. I have 2 choices on the form, upload a photo or a checkbox for no photo. I want to to do a check so if they checked no photo as well as picked a file to upload, it reports back that they need to fix it.

$userfile = $_FILES['userfile']['name'];

View 1 Replies

Difference Between Basename($_FILES['file... And $_FILES['file?

what is the different between basename($_FILES['file']['name']) and $_FILES['file']['name']

both echo the same value rite? so, what is the different between both?

View 3 Replies

Parse Error With "if (isset($_POST['min']) && Isset($_POST['max'])"

I'm making a form where one of the results is created by a range of dates. I have 2 drop down boxes that are populated with "date" data from the table and they pass it onto the results page using the "Post" method. My host is Godaddy / Linux and my table is MySQL ver 4.1 Code:

View 2 Replies

Each $_FILES

nothing shows up when I run this code from a form? I'm trying to cycle through what needs to be uploaded. I have 5 file inputs.

echo "Values submitted via FILESbr />
reset ($_FILES);
while (list ($key, $val) = each ($_FILES)) {
echo "$key => $val<br />

View 1 Replies


I have a script that allows a user to upload an image, and store that value in a database. If there is already a value in the database the script reverts to a section that allows the user to 'delete' the image and upload another one. In order to retrieve the image from a folder I am using a hidden field in some html to echo the file name then pull that into $_FILES ['imagefile']. The problem is that from the script below I get an undefined index on 'imagefile:' PHP Code:

echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN "http://www.w3.org/TR/html4/strict.dtd">
   <html lang="en">
    <form name="form1" method="post" action="" enctype="multipart/form-data">
    <input type="hidden" name="imagefile" value="<?php echo $image1; ?>">
    <p>&nbsp;</td><td><input name="submit" type="submit" value="Submit"></p>
    //    exit;
    //move image1 to the delete folder.
echo "$image1";
    if(isset( $submit ))

View 5 Replies

Put $_FILES Into A Session

I'm trying to get my $_FILES arrays into a session because I want to
move the files later to a specific directory (ie after I get a result_id
from a sql insert). No problem putting the variables in a session but I
can't move $_SESSION['userfile']['tmp_name'] anymore.
$_SESSION['userfile']['error'] is 0 so I don't really see what could be
the problem....

View 2 Replies

Weird $_FILES

I have a file input field named mainpic. PHP Code:

$main = strtolower($_FILES['mainpic']['name']);

$main is continually blank. if i do a foreach on $_FILES it says mainpic is an array but if i try to foreach mainpic it errors out. I have the correct enctype and everything. The shortcut i usually use did not work either. PHP Code:

$main = $mainpic_name;

It's working on my other sites so I'm going pretty nuts. Any ideas?

View 1 Replies

PHP's $_FILES Properties

I was wondering if there was a way to retrieve the FULL path of the location of the file before it is uploaded. Reason being is I have a form with lets say 3 places to input data. Two are text and one is a file.

However if they forget to input text into one of the input fields, it will prompt them to insert that into the field, and what I do is i assign the value of the other field to itself, so it essentially remembers what they had typed in. However I can't seem to get the full file extension of the image they are uploading. Code:

View 3 Replies

$_FILES Not Being Passed

Using a regular Input type=file called 'loadmolfile' within a form on a page where the form gets POSTed back to the same page when a 'Save' submit button is pressed. Code:

View 2 Replies


I have a PHP-script on page A that receives a file from an HTML-form. I need to immediately forward this file to another page B. On page A currently I forward the user (under certain circumstances) to page B using header ("location: page_b.php");

But unfortunately the file that was posted to page A is lost. Is there a way to forward the file to page B so that I can use the superglobal $_FILES variable on page B? I tried a very bad hack with sessions:

On page A:
$_SESSION["files"] = $_FILES;
On page B:
$_FILES = $_SESSION["files"];

I didn't really expect this to work - unfortunately it does not because the server deletes the temporary file immediately. Well, I could try copying the temporary file to a different filename but I believe there is a simpler way by just adding the file again to the header?

View 1 Replies


I have heard that it might be better using $HTTP_POST_FILES for php version 4.1 and lower
and using $_FILES for 4.1 and higher. Anyone knows what is the difference really? why not simply using $HTTP_POST_FILES on all ?

View 2 Replies


i wanna get the size of an uploaded file using $_FILES['uploadedfile']['size']. but why isnt it working. $_FILES['uploadedfile']['type'] and $_FILES['uploadedfile']['name'] is working tho.

View 3 Replies

Nothing Stored In $_FILES

I can't seem to get any data stored in $_FILES I checked in my ini file, and file upload is turned on. However, when I upload a file, and try to output anything stored in one of the $_FILES indexes, there is nothing there.

View 6 Replies

$_FILES Problem

I am trying to program a upload system.

$file_name = $_FILES['uploadFile'. $x]['name'];
$size = filesize($file_name);
$type = mime_content_type($file_name);

However, when I change to

$file_name = $_FILES['uploadFile'. $x]['name'];
$size = $_FILES['uploadFile'. $x]['size'];
$type = $_FILES['uploadFile'. $x]['type'];

Is there any problem happan in my code?

View 3 Replies

$_FILES Array

PHP Code:

$user_avatar_size = (!empty($_FILES['avatar']['size'])) ? $_FILES['avatar']['size'] : 0;
echo 'user_avatar_size' . $user_avatar_size . '<br>'
die('files:' . $_FILES['avatar']['size']);

could output this: Quote:


View 3 Replies

In_array $_FILES

This function is to preview an entry before it is submitted, my problem is when I'm uploading more than 1 new photos to a past (edited) entry (that is the only time it delves into the if statement). The line with the if statement containing the in_array function like it is will produce only the side that is uploading a new image with $temp_uploads variable. However if I inverse it to '!== false' then it only gets all the ones from the db, no matter how many times it's looped. PHP Code:

function preview($page, $edit_id) {
¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ global $db, $temp_uploads, $uploads;

¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ $table¬ ¬ = $db.$page;
¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ $fields = array_merge($_POST, $_FILES);
¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ $preview_form .= '<div class="white"></br><form enctype="multipart/form-data" action="?p='.$page.'&z=s&i='.$edit_id. '" method="post"><table class="preview" align="center">'
¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ //loop through each field in the array
¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ foreach($fields as $field => $value){
¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ ¬ //if field's value has something special that needs to be done to it EX. upload an image.

View 3 Replies

Problem Using The $_FILES

Im trying to upload files to a folder named musikk where my index file is placed. Code:

View 6 Replies


Is there any way of setting the $_FILES array without actually uploading a file through http upload?

I ask because I want to send a file that already exists on my server to be handled by my script that deals with normal uploads. The reason the file has to be sent in the $_FILES array is that this is how the upload script receives and processes files and it is zend encoded so I can't edit it!

View 2 Replies

Storing _FILES

how do you store all the information inside _FILES[] when you do a post. How long does a file stay in the temp dir before you have to move it or it gets deleted. I need to know this because I want one php file to have the upload GUI and another to actually store the file on the server but I do not know how to pass the file information between the two.

View 1 Replies

Copyrights 2005-15 www.BigResource.com, All rights reserved