Count Clicks On Play Button Of Every Song Separetly?

m just making a little script related to music portal.infact want that when everybody click on songs play button separately i can count the click of every songs in daabase because want to fetch most played tracks so through this i can show eaily most played tracks[url] i count clicks on play button of every song separetly...


Count Hits On Play Button?

m just making a little script related to music portal infact want that when everybody click on songs play button separately i can count the click of every songs in daabase because want to fetch most played tracks so through this i can show eaily most played tracks [URL]

please help me that how i count clicks on play button of every song separetly...

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/var/www/thumbs/ same name-example.jpg thumb

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Carpenters (456)

The categories table has a column hits INT(11).

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Possible Duplicate: How to set cookies for uuid my question is how to count and display clicks on a php value (since the link id changes a lot,[URL]

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When I load page for first time i get 0, after first click it echos out 1 as it should but then it doesnt go up any more. Cant see whats different 2nd time and onwards as the value should get incremented.

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THe following code (unsurprisingly) will not work

<INPUT class = "button" TYPE="submit" id="stop_button"  NAME="stop_button" VALUE="STOP"
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Any suggestions ?

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However, if they click on the [x] of the browser, the session stays alive, it does not get destroyed. How can I tell the server that if the user clicked on the [x] and closed the browser, it has to destroy the session?

I read a lot on ajax solutions with javascript and there is no window.onclose() that will help. The onunload() function does not do what I need.

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Redirect user to another website, even user clicks STOP button after a small interval of time(5 seconds).

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Set redirect user after 5 seconds even if they hit STOP button.

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PHP Code:
if ($_GET['password']!='password'){ exit; }
if (!file_exists($filepath)){ echo "no file exists"; exit();}


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If the user clicks on the back button, it shows all of the default values, but box 2 and 3 (dependants) are missing. If they click submit again, its a whole mess. What I want to do is if the user clicks on the back button, all of the fields need to go back to the default selections.

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$zip = '90210'; //change to your zipcode

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I am an absolute beginner in php & am trying to validate a form using javascript. Problem is I am checking if the textbox is left empty before the user clicks on the submit button(using javascript). On the other hand i'm using isset function of php for the same submit button so that it does not run the code unless and until the button is clicked. Due to this, the default value of text box is being entered into database. How do i prevent this? Is there an alternate function to isset for such an event?

Code: [Select]<?php
$sql="insert into testing values('$_POST[txt1]')";
$exec = mysql_query($sql);
<script type="text/javascript">
function check()

I'm using ghost text technique on my page instead of labels so the text boxes have different values at different instances and hence I cant use !empty function either. How do i unset the submit button so that it does not run the script further?

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I am working a database retrival code and I can only obtain partial data from a string.

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Update JQuery To Allow Mutiple Button Clicks To Dynamically Call/update Data Using Ajax?

i'm able to capture the first button on the page, but there are a total of 10 buttons. When I click on any of those 10 buttons, only the first button's value is called and the other ones don't update. is there a way to capture all of the buttons so they each have their own independent value and update their values so jQuery's ajax function gets the new one? the buttons are being created out of a multidimensional array loop.

$characters = $char->getCharactersListFromAccountId($_SESSION['acctid']);
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