Warning: Mysql_num_rows() Expects Parameter 1 To Be Resource, Boolean Given In?

//the error is at line 13

$questions =$_POST['question_text'];
$checkquestion=mysql_query("SELECT question_text FROM questions LIKE '$questions' ");
if(mysql_num_rows($checkquestion)) { //line 13
[code]....



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Error - Warning: Mysql_num_rows() Expects Parameter 1 To Be Resource, Boolean Given In

Seems to be outputting an error, I have no other problems with my querys formatted like this,

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:xampphtdocsincludesconfig.php on line 163
$connection=mysql_connect($db_host,$db_user,$db_pass);
mysql_select_db($db_name, $connection);
function Search($x) { // Search Ringtones Functions
$s=$_POST['s'];

[Code]...

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i got this error. here is the coding

Code: [Select]<?php
/* 
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
$dbuser="root";
$dbpswd="****";
$dbserver="localhost";
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I keep getting this error? Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in
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PHP Code:
// connect to MySQL
$connection = mysql_connect($host, $user,
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[code]....

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Mysql_num_rows() Expects Parameter 1 To Be Resource, Boolean Given?

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in

PHP Code:
<?php
require('connect.php');
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<?php
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<?php
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Im trying to connect to an ftp site and i keep getting this error

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Warning: ftp_close() expects parameter 1 to be resource, boolean given in C:Program Filesxampphtdocsclickonlinehomesftptest.php on line 36



This is my code


$ftp_server="datalink.interealty.com/DataLinkOutput/AAR/AAR_1000045403";
$ftp_user_name="******";
$ftp_user_pass="****";




// set up basic connection
$conn_id = ftp_connect($ftp_server);

// login with username and password
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);


ftp_close($conn_id);



Anyone know whats causing error?

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I get a php error...Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given

$sql = "SELECT
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FROM `pm_messages`
GROUP BY `pm_messages`.`conversation_id`
WHERE `pm_messages`.`conversation_id` = ${conversation['id']}";
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I am using simple self-created php script to change password to my wow server's website.

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Password script:

if (isset($_POST['submit'])){
change_db($realm_DB);
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i got this error.here is the coding

<?php
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.[code].....

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<?php
$con = mysql_connect("localhost","root","");
if (!$con)
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I am following this video:http://[url]....I don't understand everything i have written is right...?This is my code:

PHP Code:
<?php
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Error:

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I have tired to search this up but get nothing back.. :@This error is on line 18on line 18is
Code: [Select]if (mysql_num_rows($result) == 1) {QuoteNotice: Undefined variable: result in C:xampphtdocsExam_OnlineStaff_loginStaff_login_process.php on line 18

Warning: mysql_num_rows() expects parameter 1 to be resource, null given in C:xampphtdocsExam_OnlineStaff_loginStaff_login_process.php on line 18
Wrong Username or Password
This is the error message.
[code]...

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I am trying to select data from table but get this error message:

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This is my code:

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:S
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130.{
131.return mysql_num_rows( mysql_query( $query ) );
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When I run the program above I get this message

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<?php
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<body>
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Code: [Select]<?php
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[Code]...

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Code:
Code: [Select]<?php
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Code:

<?php
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Connects to your Database
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