Submitting Multiple Form Fields In An Array / Loop

I have the following form

<?php do { ?>
<input name="approve[]" type="checkbox" id="approve[]" value="<?php echo
$row_rs['ID']; ?>">
<select name="select">
<option value="1">option 1</option>
<option value="2">option 2</option>
<option value="3">option 3</option>

<?php } while ($row_rs = mysql_fetch_assoc($rs)); ?>

I want to acheive a loop that inserts a record into a database that enters
the id and the value they have selected (if the approve input box was

so far I have this:
foreach($approve as $aID) {
$insertSQL = "INSERT INTO TABLE('refID','optionSelected') VALUES



How do I enter the select value within this loop?
I assumed that it would be just
$insertSQL = "INSERT INTO TABLE('refID','optionSelected') VALUES


Submitting Form Multiple Times In .each() Loop - Only Last Submit Sending

I am trying to submit a form then update some values and submit it again. However, when I do this only the LAST version is being submitted. I get one error for Unsafe Javascript attempt to access frame with URL from frame with URL domain1 . Domains, Protocols and Ports must match.

form code:

<form id="hiddenform" method="post" enctype="multipart/form-data" action="" accept-charset="UTF-8" target="tintest">

the target is a hidden iframe with the id="tintest"

This is my code:

var tbody = $("#vmMainPage table:first tbody");
var lng = tbody[0].rows.length - 1;
var mnstr = "items: ";
$("#vmMainPage table:first tbody tr").each(function(i){


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