Show Value For Text Field

Sep 20, 2006

the text field is PHP Code:

<input name="page[]" type="text" size="3" maxlength="3" value="<?php echo $row_some['PAGE']; ?>" />

it show the same value at the first value in the database.

in the database.


but in my coding,it will show value 34 in each of text field value.


Show A Field Data(text)

Aug 23, 2006

How can i show a field data(text) when i move mouse over a pic (like alt text of pic)
for example your credit pic is available in a page,now u move your mouse over the credit pic and it shows your credit (like alt text in a simple image)from the My Sql.
(for example: field name in sql is is: kom ) any thing like this :

<img src="pic/me.gif" alt=" this section code is nedded " width="9" height="9">
<img src="pic/me.gif" alt=" $read from kom " width="9" height="9">

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Aug 20, 2010

I am trying to get something up where by:-> It dynamically displays input text fields that can be edited.> However I need the current id as well as the current value to display-> when a person submits the form, it updates all / or only each one that has been altered. Q:-> I need to use both the id and new value or old value when updating the database. How can this be done?Code below: of what i have attempted so far.

$sql5 = "SELECT * FROM $tableName";
foreach ($conn->query($sql5) as $row5) {

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Jan 3, 2011

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I have confirmed that when I do input the value for the custom field is it being outputted in the Post. Here is the code I am using:


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Jun 7, 2009

my home page is an insert form where the user posts what they want to buy/sell. there are two fields in the db that i'm dealing with for this problem, one is the user's postint title and the other is the content they enter. i only have the user enter the content right off the bat, but they can always login and edit their post title whenever they want. can i extract the first 30 characters from the content and submit it into the post title hidden field when they initially fill out the form?

i've tried something like,
$title = $_POST['content'];
$title = substr($title, 0, 30);
... and then in my form...
<input type="hidden" value="<?php echo $title;?>

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Sep 28, 2010

i have this edit form that allows user to edit data but the problems on the text box is that it deletes the rest of the data after the space from the first word i tried to increase the size of the varChars on mysql but did no work why it happens how can i stop from happening?? example if name elvis priesley when i try to edit it only comes elvis cuts off the other words after space this the form input

PHP Code:

<input type="text" name="name" id="name" class='text_box' value="<?php echo $_GET['name'];

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Apr 20, 2006

I have a mysql table with member data. I need to query that data for a particular member's data and then display it on the page. PHP Code:

$g = "select * from members where id = 2";
$grec = mysql_db_query($dbname, $g) or die(mysql_error());
while ($r = mysql_fetch_row($grec)){
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This particular customer changes things quite often and he may add more fields in the future. Therefore, if I use mysql_fetch_array and put in all the fieldnames, it won't catch the new ones that the customer ads. Can mysql_fetch_row be used to loop through the data and show the fieldname and corresponding data? If so, what is the code to do so?

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Feb 5, 2006

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Basically i'm looking for a way to do it with a single query not 2 (one
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Jul 4, 2007

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May 13, 2006

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Oct 20, 2009

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How do I take what was typed into first_name and last_name fields and add them together to the screen_name so when the field is submitted, it inputs the values appropriately for the screen_name field?I am looking for either a php or jQuery resolution.Would this do the trick?

<?php $screen_name = $_POST["first_name"]." ".$_POST["last_name"]; ?>
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Oct 2, 2000

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The code goes something like this


$result = mysql_query("SELECT * FROM reports WHERE target_page LIKE 'News' ORDER BY description",$db);

if ($myrow = mysql_fetch_array($result)) {

echo "
<table border=0 width=70%>n"; do { echo "
n"; printf("
</tr>n", $myrow["description"]); echo "
n"; printf("
</tr>n", $myrow["paragraph_1"]); echo "
n"; printf("
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n"; printf("
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n"; printf("

</tr>n", $myrow[""]); } while ($myrow = mysql_fetch_array($result)); echo "
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Dec 15, 2006

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in London, when i select it to update the address , i get 23 and 10 corresponding to their ids in the table. How would i change that please ? $name gets pulled from the Customers table and $city is from the City Table whose id $cityid is recorded in Custaddress. Code:

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May 18, 2010

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first_name: bob
last_name: builder

When they change say their first name to "james", the confirmation page shows their first name in bold because they changed that but the other areas are still normal text.


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Mar 4, 2011

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May 26, 2007

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Jul 23, 2007

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For example:
$string_in_database = "John's car."

-displays correctly here <textarea><?php print $string_in_database ?></textarea> and displays this - John's car.

-gets cutoff here <input type='text' value=''<?php print $string_in_database ?>' /> and displays this - John

I've tried adding slashes and stripping slashes and I just can't figure out what I need to do.

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Pound signs etc work, but having issues with & (&amp;) and trying to strip_tag at the same time?

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Dec 28, 2009

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and this code for the text field: Code: [Select]<input name="skillField" type="text" size="25">

but what I actually want is to get the text from the selected drop down item.

You can see the form here: [url].... it is the Manage Skills List section.

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Jan 31, 2007

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my field is called name. how do you say NOT empty in php.

if $row["name"] NOT EMPTY then
echo ($row["name"]);

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Feb 16, 2011

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Edit 1: I hack that I came up with that works is the following.

global $user;
$user1 = user_load(array('uid'=>1));
$prevUser = $user;
$user = $user1;
$view = views_get_view('greeting_listen');
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If a record ID has less than 4 digits, then add prefix 0's in front of them.

For example:

record #2 needs to show like AAAA0002.
record #10001 needs to be like AAAB0001.

The first part of 4 letters starts with A, if the record ID has more than 4 digits, the respected characters need to be incremented in the same manner.

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this is what i use to show the the data from mysql.



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I am using this to show the value of my custom field:

if ( function_exists('get_custom_field_value') ){
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$hostname = "";
$db_user = "";
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echo $form->label('Game Thumbnail');
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How to pass value to DB and see old one in textarea?

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GD Version 2.0 or higher
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