Show Value For Text Field

Sep 20, 2006

the text field is PHP Code:

<input name="page[]" type="text" size="3" maxlength="3" value="<?php echo $row_some['PAGE']; ?>" />

it show the same value at the first value in the database.

in the database.

page
34
43
56
34
45
65


but in my coding,it will show value 34 in each of text field value.

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Show A Field Data(text)

Aug 23, 2006

How can i show a field data(text) when i move mouse over a pic (like alt text of pic)
for example your credit pic is available in a page,now u move your mouse over the credit pic and it shows your credit (like alt text in a simple image)from the My Sql.
(for example: field name in sql is is: kom ) any thing like this :

<img src="pic/me.gif" alt=" this section code is nedded " width="9" height="9">
<img src="pic/me.gif" alt=" $read from kom " width="9" height="9">

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I am trying to get something up where by:-> It dynamically displays input text fields that can be edited.> However I need the current id as well as the current value to display-> when a person submits the form, it updates all / or only each one that has been altered. Q:-> I need to use both the id and new value or old value when updating the database. How can this be done?Code below: of what i have attempted so far.

$sql5 = "SELECT * FROM $tableName";
$functions=array();
foreach ($conn->query($sql5) as $row5) {
$functions[]=<<<END
[code]....

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I have a site that is using custom fields, and I want to either show the content for the field if the field is being used, and if the field is not being used per a Post then of course don't show the contents of the fields. Seems my code below is not correct, as it is showing the content in the else block when the Post is not using any of the custom fields.

[URL]

I have confirmed that when I do input the value for the custom field is it being outputted in the Post. Here is the code I am using:

[Code]....

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Jun 7, 2009

my home page is an insert form where the user posts what they want to buy/sell. there are two fields in the db that i'm dealing with for this problem, one is the user's postint title and the other is the content they enter. i only have the user enter the content right off the bat, but they can always login and edit their post title whenever they want. can i extract the first 30 characters from the content and submit it into the post title hidden field when they initially fill out the form?

i've tried something like,
$title = $_POST['content'];
$title = substr($title, 0, 30);
... and then in my form...
<input type="hidden" value="<?php echo $title;?>

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Sep 28, 2010

i have this edit form that allows user to edit data but the problems on the text box is that it deletes the rest of the data after the space from the first word i tried to increase the size of the varChars on mysql but did no work why it happens how can i stop from happening?? example if name elvis priesley when i try to edit it only comes elvis cuts off the other words after space this the form input

PHP Code:

<input type="text" name="name" id="name" class='text_box' value="<?php echo $_GET['name'];

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Apr 20, 2006

I have a mysql table with member data. I need to query that data for a particular member's data and then display it on the page. PHP Code:

$g = "select * from members where id = 2";
$grec = mysql_db_query($dbname, $g) or die(mysql_error());
while ($r = mysql_fetch_row($grec)){
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}

This particular customer changes things quite often and he may add more fields in the future. Therefore, if I use mysql_fetch_array and put in all the fieldnames, it won't catch the new ones that the customer ads. Can mysql_fetch_row be used to loop through the data and show the fieldname and corresponding data? If so, what is the code to do so?

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Feb 5, 2006

Is there a way to insert text into a mysql text field that already has
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string.

Basically i'm looking for a way to do it with a single query not 2 (one
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Jul 4, 2007

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Oct 20, 2009

<p>First Name <input type="text" name="first_name"> Last Name <input type="text" name="last_name"></p>
<input type="hidden" name="screen_name" value="first_name + last_name">

How do I take what was typed into first_name and last_name fields and add them together to the screen_name so when the field is submitted, it inputs the values appropriately for the screen_name field?I am looking for either a php or jQuery resolution.Would this do the trick?

<?php $screen_name = $_POST["first_name"]." ".$_POST["last_name"]; ?>
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I have a database which when queried brings back results one of which is an image name. The image name points to a subdirectory to display the image. Everything works fine but if there is no image name then the image is not found (obviously). How can I tell a result to not show the entry if it's empty?

The code goes something like this

mysql_select_db($databaseName,$db);

$result = mysql_query("SELECT * FROM reports WHERE target_page LIKE 'News' ORDER BY description",$db);

if ($myrow = mysql_fetch_array($result)) {

echo "
<table border=0 width=70%>n"; do { echo "
<tr>
n"; printf("
<td><B>%s</B></td>
</tr>n", $myrow["description"]); echo "
<tr>
n"; printf("
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</tr>n", $myrow["paragraph_1"]); echo "
<tr>
n"; printf("
<td>%s</td>
</tr>n", $myrow["paragraph_2"]); echo "
<tr>
n"; printf("
<td><IMG SRC=%s></td>
</tr>n", $myrow["image"]); echo "
n"; printf("

</tr>n", $myrow[""]); } while ($myrow = mysql_fetch_array($result)); echo "
</table>n"; } else { echo "Sorry, no records were found!"; } ?>

Any help would be appreciated

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Ex:
(editaccount.php)
first_name: bob
last_name: builder
email: bobbuilder@gmail.com

When they change say their first name to "james", the confirmation page shows their first name in bold because they changed that but the other areas are still normal text.

[Code]...

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[services_id[pk],
customer_id[fk],
date_in,date_out,room_type,room_number,
extra_ref,
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Jul 23, 2007

I have a string that contains an apostrophe or a quotation mark, stored in a DB. I can retrieve the data, and display it properly (for editing) in a textarea, but when I try to put the string in a text field, it get's cut off right before the questionable character.

For example:
$string_in_database = "John's car."

-displays correctly here <textarea><?php print $string_in_database ?></textarea> and displays this - John's car.

-gets cutoff here <input type='text' value=''<?php print $string_in_database ?>' /> and displays this - John

I've tried adding slashes and stripping slashes and I just can't figure out what I need to do.

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Jun 6, 2007

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Dec 28, 2009

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and this code for the text field: Code: [Select]<input name="skillField" type="text" size="25">

but what I actually want is to get the text from the selected drop down item.

You can see the form here: [url].... it is the Manage Skills List section.

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Jan 31, 2007

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my field is called name. how do you say NOT empty in php.

if $row["name"] NOT EMPTY then
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Edit 1: I hack that I came up with that works is the following.

global $user;
$user1 = user_load(array('uid'=>1));
$prevUser = $user;
$user = $user1;
$view = views_get_view('greeting_listen');
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If a record ID has less than 4 digits, then add prefix 0's in front of them.

For example:

record #2 needs to show like AAAA0002.
record #10001 needs to be like AAAB0001.

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this is what i use to show the the data from mysql.

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$total_pages=mysql_fetch_array(mysql_query($query));
$total_pages=$total_pages[num];
/*mycodescontinues.................*/
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what do i need to change here to show only duplicated entries according to topic field.

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I am using this to show the value of my custom field:

if ( function_exists('get_custom_field_value') ){
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<?php
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[URL]

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<?php
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