Retrieve Data From The Database?

I want to retrieve data from my database and display it in my form. How can i do that? i mean the php coding of the process.



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Retrieve Data From Database And Count The Number Of Times The Data Occurs?

I have a couple of tables in MySQL that I'm working with that do not have any relation. They do have a column of similar data (Postal Codes / Zip Codes). What I have to do with these tables is compare the postal codes from one table compare them to the postal codes from the first table and count them.

For Example. Table A has a postal code of T0A and T0B (I use only the first three characters in the postal code as this is all I need to compare against) Table B has 13 rows where the postal code matches T0A and 3 rows where the postal code matches T0B.

So the outcome would look like:

T0A = 13
T0B = 3

HOWEVER, then I need to take these and separate them by city, so since both T0A and T0B could be one city I would need to take those and add them together and get something like.

Edmonton = 16

I've been doing this with for loops and arrays. So I'm reading the data from table A into one array and the data from table b into another array. Then I compare the postal codes from table B to the postal codes in table A using nested for loops in order to count the number of occurrences of the postal codes and then I store them in another array. This is all fine and dandy however separate the counts into their correct cities and I'm sitting here thinking there must be an easier way to do this.

Structure - Table A

jos_postalzip_redirect | CREATE TABLE `jos_postalzip_redirect` (
`id` int(11) NOT NULL auto_increment,
`country_code` varchar(2) NOT NULL,
`prov_state_code` varchar(2) NOT NULL,
`city` varchar(60) NOT NULL,
`postal_zip` varchar(6) NOT NULL,
`email_address` varchar(60) default NULL,

[Code]....

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I would like to store 'Juan' in variable $first and 'Punkista' in variable $last.

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PHP Code:
<?php
mysql_connect("localhost", "root") or
die ("Check your server c
[code]............

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PHP Code:

require('includes/cloud.php');
  $query = "select products_name from " . TABLE_PRODUCTS_DESCRIPTION . "";
  $text_content = mysql_query($query);
  echo($text_content); 

It echos the error Resource id #45

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i have googled past some days but i couldn't find the answers. all are saying and giving values directly into tables and they were generated it. But I need retrieve it directly from my database. i wanna to get it directly from queries....

[Code]....

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Now is my question how to get the column names in excel (above the records).

PHP Code:

<?php
$DB_Server = "localhost";        //your MySQL Server 
$DB_Username = "username";                 //your MySQL User Name 
$DB_Password = "password";                //your MySQL Password 
$DB_DBName = "database";

[Code]....

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[code]....

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course 3, description, date, authority 1
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course 5, description, date, authority 3
course 6, description, date, authority 3
...
etc. etc.

I want to display the results more like this:

[Code]....

I'm stumbling around blind here at the moment. I guess I want each authority to be an array $authorities[], which contains the relevant course data. Er... yeah that's as far as I've gotten. I'll need all this to work with a while loop, so that my html can be generated dynamically. Every kind of code or pseudo-code I try and write just makes my brain dribble out of my nose a little.

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this is the source code for ReadID.htm

<html>
<head>
<title>Update Details</title>

[code]..........

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Php
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[Code]....

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Here is my code:

JavaScript in a different file called divUpdate.php

<script type="text/javascript"
src="http:[url]....
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[code]...

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[Code].....

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