How Do I Control Text Box Pre-Filled Entries

Can someone tell me how to control whether or not a text box is automatically pre-filled. In other words, on some web sites, when you visit them, the username and password automatically fills itself. But on other web sites you have to fill in the username and password each time you visit them.

There is one web site, Yahoo! dot com, where the username and password text boxes are never pre-filled. I have to type in my username and password for Yahoo! dot com each time I restart my browser. It didn't used to be that way. Yahoo!'s web site used to automatically pre-fill the username and password text boxes.

The web site that I'm working on uses cookies. I suppose that I could put a cookie $Name variable in a text box - but there may be a better way of doing it, though.



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Keep Control While Passing Form Entries

I have the following code in an intermediate file, separate.php, passing values from a form to a receiving file: form -> separate.php file -> vendor's receiving file

<?php
$url="https://receivingsite.com/receive.jsp?";
foreach($_POSTas$key=>$value){
$url.="$key=".urlencode($value)."&";}
header("Location:$url");?>

I place other code (all working), ahead of the code in question. Then, the portion of the other code that sends an email to me containing the values from the form, still does that. The portion of the other code that opens another page, does not open it any more.

Instead, a nuisance (to me) confirmation page generated by the vendor's receiving file opens instead of the page I specified in my other code. This is the part of the other code that does not open any more:

print "<meta http-equiv="refresh" content="0;URL=http://mywebsite.com/next.htm">";
I have to send to their receiving file with the confirmation page because the regular one they designed for this purpose (no confirmation page) requires that the form's redirect field be included, and that is a problem to me (not to most of their customers) because I have two buttons in the form going to two different pages, instead of one button like all their other customers would have.

The receiving file (confirmation page) that I have to send to was designed with a different use in mind, but I have to send to it because the regular one must receive a form field that I do not want to include. So it seems that I need to replace header ("Location: $url"); with something else, or make some other change or addition.

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Here is the source code I use: (changed some parts of privacy).

PHP Code:

<?php
require_once('includes/connTCM.php');
$tcm_lang_file='includes/lang_nl.php';
require_once($tcm_lang_file);

[Code].....

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That never was much of a problem (and i didn't find a quick solution) until recently traffic numbers increased and since then MySql reports the "to many connections" Problems repeatedly, even so 350+ of those connections are in "sleep" state. Also a server can't get a mysql connection even if there are sleeping connection to that same server. All those connections vanish when a apache server is restated.

The PHP Code used to create the Database connections uses the normal "mysql" Module, the "mysqli" Module, PEAR::DB and Zend Framework Db Adapter. (Different projects). NONE of the projects uses persistent connections. Raising the connection-limit is possible but doesn't seem like a good solution since it's 450 now and there are only 20-100 "real" connections at a time anyways.

My question: Why are there so many connections in sleep state and how can i prevent that.

-- Update:..........

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<?php
// Initiate MYSql Details
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$MYSQL_Username = "root"; // MySQL Username.
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[Code].....

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That I can resolve with a simple WHERE name="$name", the 'name' column being indexed.

But here comes the problem. When such select yields 0 entries, I want to find SIMILAR names, matching as much of characters from the left as possible. For example, if I'm looking for "John Doe", I want the script, failing to find him, to show me similars like:

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if(isset($_GET['comments'])) { $comments = $_GET['comments'];
}
if (!isset($_GET['comments'])) {
$comments = "";
}
if ($comments == "ok") {
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now when the user clicks on comment it just includes the comment text area but here there is more then one threads on the same page or I can say more then one post on the same page so when the user clicks on "comment" on post one all the other posts get the text area below it.what I need here is when the user clicks comment on post "1" the text area appear below post "1" and not 2 or 3 or any other one on this page.
I hope I got you to the point that I want.

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this is the line in the Post's add view that show the select.

echo $this->Form->input('user_id');
PostsController :
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// Some other code
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Although I know how to display only the username of the currently logged-in user, I don't know how to control the content to show in $this->Form->input() because if I use a variable that is not part of the "Post" model , it's shown , but as the label for the input.

P.S. I've been trying to find this information on the cookbook , but I haven't been able to find anything specific to my situation :(

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Edit

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